Answers
We can remove the brackets - called expanding the brackets - using FOIL which stands for First Outer Inner Last which is a procedure to follow to expand the brackets:For the general case (A + B)(C + D)A×C + A×D + B×C + B×DNow we apply this to (x − 4)(x − 7)x × x + x × -7 + -4 × x + -4 × -7= x^2 − 7x − 4x + 28Now we simplify:= x^2 − 11x + 28
05 May 2016
There is a cheat for this....(x-4)(x-7), you have two 'x' that you are multiplying together so it will always be in the form x^2+x+n (n just means any number).You have two x's so you get x^2 at the startYou have (-4)x(-7) so you get n=+28 ( a minus times a minus gives a plus) at the end.Now for the middle term (-4)+(-7) = -11 which is the coefficient or number next to the x term.Altogether you get:X^2-11x+28Simply put: add the numbers together to get the coefficient of x and multiply them together to get the number at the end.Easy Peasy
08 May 2016
(x-4)(x-7)= x^2 -7x -4x +28= x^2 -11x + 28
09 May 2016
For questions like this, you have to make sure you times all the terms by the other ones. This means you do x*x + x*(-7) + (-4)*x + (-4)*(-7) Simplifying this it would be x^2 - 7x - 4x + 28= x^2 -11x +28Hope that helps!
10 May 2016
Sketch216165729.png
21 May 2016
This is just a matter of multiplying the brackets out. So, do it systematically:x multiplied by x is x^2 (x squared that is)x multiplied by -7 is -7x -4 multiplied by x is -4x-7 multiplied by -4 is 28So, now we're left with x^2-7x-4x+28 and to simplify we combine the -4x and -7x to -11x so now the final equation is x^2 -11x +28. Hope that helps.
30 May 2016
answer_tutor.png
01 June 2016
In maths, whenever a set of numbers/letters are in a pair of brackets, next to another set of similar brackets - this means you need to multiply the two sets of brackets with each other.Work with one set of numbers/letters at a time. Do not multiply the numbers within a set of brackets with each other (unless instructed to do). Multiply the chosen number/letter with all the chosen number/letters in the other brackets. keep all the signs. e.g. x times x and x times -7 gives the following:-sx^x (x squared) and -7x. Work through all the numbers from the first set of brackets and then add all the similar ones until you get your answer
02 June 2016
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09 June 2016
The main best approach it to take the variables in the first bracket and they each multiply both variables in the second bracket.So the first variable x multiplies both variables in the second brackets.Then we take the second variable and it multiplies both variables in the second bracket .Then we collect like terms and add where possible .
09 June 2016
Дискриминантное уровнение
12 June 2016
First we multiply out the brackets.(x-4)(x-7)x*x, x*-4, x*-7, -4*-7=x^2 -4x -7x +28Then we simplify=x^2 -11x +28And that's all there is to it.If you need any further help with similar problems, get in touch to organise a lesson!
15 June 2016
(x-4)(x-7)now start to multiply, x*x, x*-7, -4*x, -4*-7=x^2 -4x-7x+28Minus the common terms, -4x-7x = -11xoverall answer: x^2 -11x +28thats it !I hope this will help you.Always feel free to ask as many questions as you can.
22 June 2016
(x-4)(x-7)now start to multiply, x*x, x*-7, -4*x, -4*-7=x^2 -4x-7x+28Minus the common terms, -4x-7x = -11xoverall answer: x^2 -11x +28thats it !I hope this will help you.Always feel free to ask as many questions as you can.
22 June 2016
Maths_Question_1_Tutor_Hub.docx
01 July 2016
(x-4)(x-7) = x(x-7) - 4(x-7) =x2-7x-4x+28 =x2 - 11x + 28
03 July 2016
Note: The x2 means it's squared. That's the only way it can be typed on the tutorhub textbox. The "2" in this case is a superscript. I hope this clarification is helpful. Thank you.
03 July 2016
SOLUTION.docx
03 July 2016
Right there in my uploaded document is a more professional and appropriate way of doing it.
03 July 2016
(x-4)(x-7)now start to multiply, x*x, x*-7, -4*x, -4*-7=x^2 -4x-7x+28Minus the common terms, -4x-7x = -11xoverall answer: x^2 -11x +28thats it !
15 July 2016
Are you still in need of help with this topic in algebra?
07 August 2016
(X-4 ) (x-7)First we fill open the first bracket and multiply them by next bracket, as shown belowX × (x-7) -4 ×(x-7)After that, multiply x and 4 with brackets, as shown below,x^2 -7x -4x +28= x^2 -11x +28
19 October 2016
(x-4)(x-7)=X^2 -7x -4x + 28= x^2 -11x +28 (answer)
31 March 2017
x*x - x*7- 4*x+ 7*4 (* sign is for multiplication)=x^2 -7x -4x +28=x^2-11x+28
09 April 2017
(x-4)(x-7)by multipying we get=x^2-4x-7x+28=x^2-11x+28
18 December 2017
x^2 - 7x - 4x + 28x^2 -11x + 28
14 January 2018
(x-4)(x-7) = x^2 -7x -4x + 28 = x^2 -11x + 28
22 April 2018
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