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(x-4)(x-7) = x^2 -7x -4x + 28

                     = x^2 -11x + 28

x^2 - 7x - 4x + 28

x^2 -11x + 28

(x-4)(x-7)

by multipying we get

=x^2-4x-7x+28

=x^2-11x+28

x*x - x*7-  4*x+ 7*4 (* sign is for multiplication)

=x^2 -7x -4x +28

=x^2-11x+28

(x-4)(x-7)

=X^2 -7x -4x + 28

= x^2 -11x +28 (answer)

(X-4 ) (x-7)

First we fill open the first bracket and multiply them by next bracket, as shown below

X × (x-7) -4 ×(x-7)

After that, multiply x and 4 with brackets, as shown below,

x^2 -7x -4x +28

= x^2 -11x +28

Are you still in need of help with this topic in algebra?

(x-4)(x-7)

now start to multiply, x*x, x*-7, -4*x, -4*-7

=x^2 -4x-7x+28

Minus the common terms, -4x-7x = -11x

overall answer: x^2 -11x +28

thats it !

Right there in my uploaded document is a more professional and appropriate way of doing it.

Note: The x2 means it's squared. That's the only way it can be typed on the tutorhub textbox. The "2" in this case is a superscript. I hope this clarification is helpful. Thank you.

(x-4)(x-7) = x(x-7) - 4(x-7)

                =x2-7x-4x+28

                =x2 - 11x + 28

(x-4)(x-7)

now start to multiply, x*x, x*-7, -4*x, -4*-7

=x^2 -4x-7x+28

Minus the common terms, -4x-7x = -11x

overall answer: x^2 -11x +28

thats it !

I hope this will help you.

Always feel free to ask as many questions as you can. 


(x-4)(x-7)

now start to multiply, x*x, x*-7, -4*x, -4*-7

=x^2 -4x-7x+28

Minus the common terms, -4x-7x = -11x

overall answer: x^2 -11x +28

thats it !

I hope this will help you.

Always feel free to ask as many questions as you can. 


First we multiply out the brackets.

(x-4)(x-7)
x*x, x*-4, x*-7, -4*-7
=x^2 -4x -7x +28

Then we simplify

=x^2 -11x +28

And that's all there is to it.


If you need any further help with similar problems, get in touch to organise a lesson!

Дискриминантное уровнение

The main best approach it to take the variables in the first bracket and they each multiply both variables in the second bracket.So the first variable x multiplies both variables in the second brackets.Then we take the second variable and it multiplies both variables in the second  bracket .Then we collect like terms and add where possible .

In maths, whenever a set of numbers/letters are in a pair of brackets, next to another set of similar brackets - this means you need to multiply the two sets of brackets with each other.

Work with one set of numbers/letters at a time.  Do not multiply the numbers within a set of brackets with each other (unless instructed to do).  Multiply the chosen number/letter with all the chosen number/letters in the other brackets.  keep all the signs.  e.g. x times x and x times -7 gives the following:-

sx^x (x squared) and -7x.  Work through all the numbers from the first set of brackets and then add all the similar ones until you get your answer

This is just a matter of multiplying the brackets out. So, do it systematically:

x multiplied by x is x^2 (x squared that is)

x multiplied by -7 is -7x

-4 multiplied by x is -4x

-7 multiplied by -4 is 28

So, now we're left with x^2-7x-4x+28 and to simplify we combine the -4x and -7x to -11x so now the final equation is x^2 -11x +28. Hope that helps.

For questions like this, you have to make sure you times all the terms by the other ones. This means you do 

x*x + x*(-7) + (-4)*x + (-4)*(-7) 

Simplifying this it would be 

x^2 - 7x - 4x + 28

= x^2 -11x +28

Hope that helps! 

(x-4)(x-7)

= x^2 -7x -4x +28

= x^2 -11x + 28

There is a cheat for this....

(x-4)(x-7), you have two 'x' that you are multiplying together so it will always be in the form x^2+x+n (n just means any number).

You have two x's so you get x^2 at the start

You have (-4)x(-7) so you get n=+28 ( a minus times a minus gives a plus) at the end.

Now for the middle term (-4)+(-7) = -11 which is the coefficient or number next to the x term.

Altogether you get:

X^2-11x+28

Simply put: add the numbers together to get the coefficient of x and multiply them together to get the number at the end.

Easy Peasy

We can remove the brackets - called expanding the brackets - using FOIL which stands for First Outer Inner Last which is a procedure to follow to expand the brackets:

For the general case (A + B)(C + D)

A×C + A×DB×C + B×D

Now we apply this to (x − 4)(x − 7)

x × x + x × -7 + -4 × x + -4 × -7

= x^2 − 7x − 4x + 28

Now we simplify:

= x^2 − 11x + 28

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