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http://www.analyzemath.com/calculus/limits/squeezing.html
A correction should've been added,that when A approaches 0, sin A/A approaches 1 To my knowledge they are two of basic theorems in limits lim A->0 [sin A/A] = 1 and lim A->0 [tan A/A] = 1

Hi Amelia,

Your answer is correct and you show a clever method. Two quick points, 

  • How do you know lim A->0 A/sin A =1 and lim x->2 tan(x-2)/(x-2)=1? 

If these are given to you then great, if not how could you prove these assertions (perhaps think about 0/0) ?

I'd be happy to explain this if you need any further help. Best wishes, Tim 


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