Answers
Use the formulae to find the roots of a quadratic equation.
08 November 2017
The roots of a function are the x intercepts.By definition the y coordinate of points lying on the x axis is 0.therefore ,to find the root of a quadratic function ,we setf(X) = 0 and solve the equation ax^2+bx+c=0
09 November 2017
The roots of a function are the x intercepts.By definition the y coordinate of points lying on the x axis is 0.therefore ,to find the root of a quadratic function ,we setf(X) = 0 and solve the equation ax^2+bx+c=0
09 November 2017
The best method is to use the quadratic formula.Given: ax^2+bx+c=0 is a quadratic equation .Then its roots areroot 1= (-b+square root of b^2-4ac)/2aroot 2=(-b-square root of b^2-4ac)/2ahope it helps.
09 November 2017
If you have a quadratic equation, ax^2+bx+c, the roots are the numbers that make this equal to zero, which means you need to solve the equation ax^2+bx+c=0. The geometrical interpretation of this is that you find the coordinates of the points that your curve cuts the x-axis (because y=0). In some occasions it is easier to find the roots by factorising. Example: x^2-5x+6=0. We need two numbers that multiply to give 6 (the constant term) and add to give 5 (the coefficient of x). It is always easier to "guess" these numbers from their product. In our case these numbers are -3 and -2, because (-3)x(-2)=6 and -3-2=-5. Then your quadratic equation can be written in the form (x-3)(x-2)=0. A bracket times another bracket is equal to zero. This means that the first bracket is zero, so x-3=0 which means that x=3, or the other bracket is zero, so x-2=0 hence x=2. Hence your roots are x=2 and x=3. Unfortunately not all the quadratics are factorable. Why? Because in some occasions the roots are irrational numbers or fractions. In that case, we use the quadratic formula. Example x^2+x-1=0. It is quite clear that I cannot find two numbers that multiply out to give -1 and add up to +1. The formula is x=(-b+/-sqrt(b^2-4ac))/2a, so all you have to do is determine the values of a, b and c and substitute in the formula. a is the coefficient of x^2 (the number times by x^2). In our case, a=1. B is the coefficient of x (the number times by x). In our example, b=1, and c is the constant (the number without any x's, and in our case it is c=-1 (NEVER forget the signs).When we substitute we get x=(-1+/-sqrt(1^2-4x1x(-1)))/2x1=(-1+/-sqrt5)/2Thus, the first root will be (-1+sqrt5)/2 and the other (-1-sqrt5)/2.I hope I did help :-)
09 November 2017
ax^2+bx+c = 0, this is one standard form of quadratic equation, if you want to find the root of this quadratic equation, you can have two roots for thisroot 1 = -b+(square root of ((( b^2)-4ac)/2a)root 2 = -b-(square root of ((( b^2)-4ac)/2a)
10 November 2017
x1 = (-b + sqrt(b*b-4*a*c)) / (2*a)x2 = (-b - sqrt(b*b-4*a*c)) / (2*a)this solution are real when b*b-4*a*c >=0
10 November 2017
This can be done by factorising or using the quadratic formula. Factorising is the easiest option but if the equation is not factorisable then the quad ration formula can also be used.
13 November 2017
well, you can find roots of a quadratic equation ax^2+bx+c=0 either by factorising or by using quadratic formula. Quadratic formula for finding roots :x1 = (-b + sqrt(b*b-4*a*c)) / 2*ax2 = (-b - sqrt(b*b-4*a*c)) / 2*a
15 November 2017
You can find roots of a quadratic equation ax^2+bx+c=0 simply sub in your values and your done!
16 November 2017
IXL_-_Solve_a_quadratic_equation_using_square_roots__Grade_10_maths_practice_.pdf
01 December 2017
IXL_-_Solve_a_quadratic_equation_using_square_roots__Grade_10_maths_practice_.pdf
01 December 2017
You can solve for x in a quadratic equation by factorising.
02 December 2017
There are several options:Factorising [ Putting them in to two pairs of brackets - e.g (x+2)(x+3)]Completing the squareQuadratic formulaSketching the graph
08 December 2017
the formula for finding roots of a quadratic equation is-b+sqrt((b^2-4ac)/2a)-b-sqrt((b^2-4ac)/2a)
18 December 2017
A quadratic equation is any equation in the form ax2 + bx + c = 0 where a ≠ 0. Any quadratic equation can be solved with the formula x = (-b +/-√(b2 - 4ac))/2a. Write your equation in the quadratic form. The official definition of a quadratic equation is a second-order polynomial equation expressed in a single variable, x, with a ≠ 0.[1] In simple terms, this just means that it's an equation with one variable (usually x) where the highest exponent of the variable is 2. In general terms, we can write this as ax2 + bx + c = 0To get an equation in quadratic form, just get all of the terms on one side of the equals sign so that you have 0 on the other side. For example, if we want to get the equation 2x2 + 8x = -5x2 - 11 in quadratic form, we can do it like this:2x2 + 8x = -5x2 + 112x2 + 5x2 + 8x = + 112x2 + 5x2 + 8x - 11 = 07x2 + 8x - 11 = 0 . Notice that this is in the standard ax2+ bx + c = 0 form mentioned above.and then find the value of a, b, c and then apply the formula to find the value of x.
25 December 2017
To find roots of quadratic equation given as ax^2+bx+c=0, where a, b and c are coefficients and "a" is not equal to zero, there are different sets of conditionsStep 1- Determine discriminant, D= (b^2-4ac)Step 2- Check, if D>0, then roots are real and equal, if D=0, then roots are real and distinct, if D<0, then roots are complex and conjugatesStep 3- find x1= -b +sqrt(D)/2aStep4- find x2= -b-sqrt(D)/2a These are the roots.
26 December 2017
Consider_the_quadratic_equation.docx
01 January 2018
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