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Remember: Always deal with brackets first.

When there is a negative just outside the brackets, it is the same as it being negative 1. So:

8x -1(3x+10) = 34

To get rid of the brackets, multiply -1 x 3 and -1 by 10. That gives:

8x - 3x - 10 = 34

Get the x's on one side and the numbers on the other. The x's are already conveniently on the same side. However, you need to move the 10 to the right side, so change the sign from negative to positive:

8x - 3x = 34 + 10

Subtract on left and add on right:

5x = 44

You want x alone, without the 5. 5x just means 5 times x. To get rid of multiplication, you need to divide. Divide both sides by 5. 

5x ÷ 5 = 44 ÷ 5

That will erase the 5 from the left side. On the right side, another way to write 44 ÷ 5 is as the fraction 44 over 5. They mean the same thing. So:

x = 44/5

That is the fraction 44 over 5. Can we simplify it? Not really, since you can't divide an even number like 44 by 5. So, the answer you have is complete. 

P.S. You only need to write it as a decimal if the question asks you to (for example, to give your answer to 1 decimal point).

If 8x -(3x + 10) = 34

Step 1: Collect like terms:  8x - (3x + 10) = 5x - 10

Step 2: 5x - 10 = 34

Step 3:   Add 10 to both sides. 5x = 44

Step 4:  Divide both sides by 5 so x = 44/5 = 8.8

Exam tip:  you can check the answer by substituting your 'x' value back into the equation to achieve a value of "34".  This is useful in exams to do a quick check! 

1. multiply out the brackets 8x - 3x-10 =34

2. gather the x values   5x - 10 = 34

3. gather the whole numbers on oneside and x values on the other side  5x = 34+10

4. so therefore 5x =44

5. x= 44/5 OR x= 8.8

The - gets multiplied inside so it becomes  8x-3x-10=34.now taking x terms 5x-10=34...taking all the numerical to one side....5x=34+10.....5x=44.....to find the value of x...the 5 should be taken to other side where it gets divided....x=44/5

The - in front the brackets affect every term inside:


Now you can proceed as usual, add 10 in each side to isolate the terms with x



Divide by 5 on each side



so u want to find x in ur question 


getting x terms to a side and numbers to one side





or u can do it as adding -10 on both sides



divide with 5 on  both sides




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