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Our month to find out how little we could spend and still survive. Up to this point, we’d been Christmas and Easter frugalists, dipping in and out of fiscal prudence where it suited us, saving enough to ensure ourselves a spot in retirement, but also buying things like a handcrafted turquoise- and- brown embroidered collar ........

• I don't understand what 'ensure ourselves a spot in retirement,' means. Please help me.

What is the result of squre root of (e)?

Chemistry Investigatory Projects Experiments. (Analysis, Tests,Titration). Please suggest. i am in class 11

Solve for x

Students often struggle with the amount of poetry on most GCSE courses. Tell me how you feel about poetry … and more specifically about studying the stuff.

Were i will write -um,-us , -ide etc. End of any chemical name

I didn't realise that he was a teacher. That's why I didn't write anything.

I'm not sure how answers are marked in A level Mathematics exams (if it counts, I'm sitting for the CIE board) but when I am doing practice questions based on a book, sometimes my answer may differ by a few hundredths or tenths (usually the third significant figure). When this happens, I usually assume that my calculation is correct and that the difference simply happens because of a choice I use to use or not use the correct form, not the one rounded off to 3 s.f. Would my marks be affected by these differences in an exam and if they do, when do I know whether I should use the rounded off figure or the exact form?

For instance in the work I've recently done, the question comes in 2 parts, the first is that I need to find the area of the sector and the second is the area of the chord of said sector. What I did was subtract the area of triangle from my previous answer but my answer was off by 2 hundredth. I did the calculation again using the correct form of the sector, not the one rounded to 3 s.f. and got the answer written in the answer booklet.

Would my answer be considered correct?

5/6:x::5/9:4/5

sin theta = (under root 3 + 1) divided by 2 times under root 2 cos theta = (under root 3 - 1) divided by 2 times under root 2 Find the value of theta. Please look at the shared image.